Question

Determine the resistance of a 564 m length of aluminum conductor whose rectangular
cross section is 4 cm by 2 cm. Take, p = 2.826x 10-8 ohm-m.​

please answer me

Answer 1

given :- l = 564m.

a = (4×2)cm = 8cm = 0.08m.

rho (p) =2.826×10^-8.

As we know that ; R = p L/A..

therefore , R = (2.826×10^-8 ×564)/0.08

R = 19923.3×10^-8...