Determine the self inductance of a coaxial cable of inner radius ‘a’ and outer radius ‘b’.
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Explanation:
Cylinder:
h=20 cm
r=1.5 cm
Sphere:
r=1.5 cm
Number of spheres · Volume of sphere=Volume of cylinder
n · (4/3)πr^3=πr^2h
n= πr^2h
(4/3)πr^3
π gets canceled.
n=r^2h
(4/3)r^3
n=1.5·1.5·20
(4/3)·1.5·1.5·1.5
The 2 1.5 gets canceled.
n=20
(4/3)·1.5
n=10
Therefore 10 spheres can be made.
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