Question

Determine the series limit of paschen series of hydrogen spectrom​

Answer 1

Answer:

For Paschen series

v

=

λ

1

=R[

3

2

1

−

n

2

1

];n=4,5,6...

For first member of Paschen series n=4

λ

1

1

=R[

3

2

1

−

4

2

1

]⇒

λ

1

1

=

144

7 R

⇒R=

7λ

1

144

=

7×18800×10

−10

144

=1.1×10

−7

For shortest wave length n=∞

So

λ

1

=R[

3

2

1

−

∞

2

1

]=

9

R

⇒λ=

R

9

=

1.1×10

−7

9

=8.225×10

−7

m=8225 A

o

Answer 2

Answer:

PLS make my answer brilliant PLS

Explanation:

The series limit for the Paschen series of hydrogen spectrum occurs at 8205.8A Calculate. (a) Ionization energy of hydrogen atom. (b) Wave length of the photon that would remove the electron in the ground state of the hydrogen atom.