Question

Determine the set A={x|x^2 +x>2}

Answer 1

x² = -2

x =√2i

√2i isn't a real number. Hence A ={ Ø }

Therefore, the set A is empty.

Answer 2

Answer:

${x}^{2} + x > 2 \\ \\ {x}^{2} + x - 2 > 0 \\ \\ {x}^{2} + 2x - x - 2 > 0 \\ \\ x(x + 2) - 1(x + 2) > 0 \\ \\ (x - 1)(x + 2) > 0 \\ \\ set \: \: a = ( - \infty \: ... - 2)union(1..... \infty )$