Determine the sine of the angle between the vector (3i^+j^+2k^)and(2i^-2j^+4k^).
Answers
Answered by
2
Explanation:
sin theta = 6-2+8/{√9+1+4 √4+4+16}
=sin inverse 【12/ {√14 × 2√6 }】
Similar questions
Physics,
3 months ago
India Languages,
3 months ago
Math,
3 months ago
Math,
6 months ago
Political Science,
6 months ago
India Languages,
11 months ago
Chemistry,
11 months ago
Biology,
11 months ago