Question

Determine the slope and the inclination with the positive direction of the
x-axis for the line graph of the following:
3Y = V3 X + 1​

Answer 1

Answer:

What is the inclination of the line x- √3y + 1 = 0 with the positive X-axis?

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Thanks A2A.

Inclination of a straight line with respect to positive x-axis is called slope.

Method 1:

x−3–√y+1=0

⇒3–√y=x+1

⇒y=13–√x+13–√

In slope - intercept form: y=mx+x , m is called the slope. Comparing the given equation with the above standard form, we get

m=13–√

Method 2:

Differentiating the given equation with respect to x, we can obtain the slope of straight line as follows:

⇒1−3–√y′+0=0

⇒y′=13–√=m

m=13–√

Hope this helps you :)