Question

determine the smallest 3-digit no. exactly divisible by 6,8,12

Answer 1

first we have to find ,smallest number,who is divisible by 6,8,12 by using l.c.m
l.c.m of 6,8,12 = 24
there 24*2,24*3,24*4,and 24*5 are also divisible by 6,8,12
but 24*2=48, 24*3=72 ,24*4=96 are two digit numbers ,so smallest no. ,divisible by 6,8,12 =24*5=120

Answer 2

Answer:

The required three digit number is 120 which exactly divisible by 6,8,12.

Step-by-step explanation:

To find : Determine the smallest 3-digit no. exactly divisible by 6,8,12 ?

Solution :

To get the number divisible by 6,8 and 12 we have to find the LCM of the numbers.

2 | 6  8  12

2 | 3  4  6

2 | 3  2  3

3 | 3  1  3

  |  1  1  1

So, $LCM(6,8,12)=2\times 2\times 2\times 3$

$LCM(6,8,12)=24$

As 24 is the number which is divisible by 6,8,12 but it is of two digit number.

As 24 is divisible so $24\times 2,24\times3,24\times4,24\times5,..$ were also divisible.

$24\times 2=48\\24\times 3=72\\24\times 4=96\\24\times 5=120$

As 120 is the three digit number.

Therefore, The required three digit number is 120 which exactly divisible by 6,8,12.