Math, asked by sian6, 3 months ago

determine the smallest 3-digit number which is exactly divisible by 8 , 10 and 12. ​

Answers

Answered by brightest98
2

Answer:

To find out the largest 3-digit number which is exactly divisible by 8, 10 and 12

first let us calculate the L.C.M 8, 10 and 12

L.C.M of 8, 10, 12 = 2 x 2 x 2 x 3 x 5

Hence, LCM of 8, 10, 12 = 120

We have to find the greatest 3 digit multiple of 120

Therefore, the number is

120 x 8 = 960

120 x 10 = 1200

120 x 12 = 1440

The 1200 and 1440 are not 3-digit numbers.

Hence, the greatest 3- digit number exactly divisible by 8, 10 & 12 is 960.

Verification

Now, let us check whether 960 is divisible by 8, 10 and 12.

960 ÷ 8 = 120

960 ÷ 10 = 96

960 ÷ 12 = 80

So the greatest 3-digit number is 960.

Answered by dalichandchandel2829
1

Answer:

120

Step-by-step explanation:

take lcm of 8,10,12 is 120.

120 is the no. that is divisible by 8,10,13

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