Math, asked by vaibhavimishra7761, 1 year ago

Determine the smallest 3-digit number which is exactly divible by 6,8 and 12

Answers

Answered by Swarup1998
1
➡HERE IS YOUR ANSWER⬇

6 = 2 × 3

8 = 2 × 2 × 2

12 = 2 × 2 × 3

So, lcm of 6, 8 and 12 is

= 2 × 2 × 2 × 3 = 24

Largest three digit number = 999

Now,

999 = 24×40 + 39

So, remains = 39.

Therefore, the required 3 digit number is

= 999 - 39

= 960

⬆HOPE THIS HELPS YOU⬅
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