Determine the smallest 3-digit number which is exactly divible by 6,8 and 12
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➡HERE IS YOUR ANSWER⬇
6 = 2 × 3
8 = 2 × 2 × 2
12 = 2 × 2 × 3
So, lcm of 6, 8 and 12 is
= 2 × 2 × 2 × 3 = 24
Largest three digit number = 999
Now,
999 = 24×40 + 39
So, remains = 39.
Therefore, the required 3 digit number is
= 999 - 39
= 960
⬆HOPE THIS HELPS YOU⬅
6 = 2 × 3
8 = 2 × 2 × 2
12 = 2 × 2 × 3
So, lcm of 6, 8 and 12 is
= 2 × 2 × 2 × 3 = 24
Largest three digit number = 999
Now,
999 = 24×40 + 39
So, remains = 39.
Therefore, the required 3 digit number is
= 999 - 39
= 960
⬆HOPE THIS HELPS YOU⬅
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