Math, asked by yumiko7426, 10 months ago

determine the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively

Answers

Answered by abhijeetkumark

By subtraction we get
28-8=20
32-12=20
Now HCF 20and 20 is =20
Therefore the smallest number which leave remainder 8 and 12 when divided by 28 and 32 respectively.

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