Math, asked by anupamakumarikanti, 2 days ago

Determine the smallest number which when divided by 16 28 40 and 77 leaves 7 as remainder in each case​

Answers

Answered by meghnamohanty011
1

Answer:

The smallest number which divides 16,28,40 and 77 is 6160.

Answered by Anupama123456
0

Answer:

16 = 2 x 2 x 2 x 2

28 = 2 x 2 x 7

40 = 2 x 2 x 2 x 5

77 = 7 x 11

LCM (16, 28, 40, 77) = 2 x 2 x 2 x 2 x 5 x 7 x 11 = 6160

Step-by-step explanation:

LCM of 16, 28, 40 and 77 is 6160. LCM stands for Least Common Multiple or the Lowest common multiple also known as LCD Least Common Divisor is the positive integer that is a common multiple to the given set of numbers. Here the given set of numbers are 28, 36, 45 and 60. The smallest common multiple for all these numbers among many is 6160, and hence it is the LCM

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