Math, asked by tv065949, 8 hours ago

Determine the smallest number which when divided by 16, 28, 40, and 77 leaves 7 as remainder in each case ? ​

Answers

Answered by alfajahmad033
5

Answer:

The smallest number, which when divided by 16,28,40,77 leaves same remainder 7

=LCM (16-7,28-7,40-7,77-7)

=LCM (9,21,33,70)

=6930

So 6930,when divided by 16,28,40,77 leaves same remainder 7.

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