Determine the smallest number which when divided by 16, 28, 40, and 77 leaves 7 as remainder in each case ?
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The smallest number, which when divided by 16,28,40,77 leaves same remainder 7
=LCM (16-7,28-7,40-7,77-7)
=LCM (9,21,33,70)
=6930
So 6930,when divided by 16,28,40,77 leaves same remainder 7.
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