determine the smallest number which when increased by 27 is exactly divisible by 660 and 594
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Let the number be "x"
x=(LCM of 660and594) - 27
x= 1980-27
x=1953
Hope this helps u
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x=(LCM of 660and594) - 27
x= 1980-27
x=1953
Hope this helps u
Plz mark as brainliest
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