Question

Determine the specific gravity of liquid having viscosity of 0.007 poise and kinematics viscosity of 0.042.

Answer 1

Answer:

The specific gravity of a liquid has a viscosity of 0.007 poise and the kinematic viscosity of 0.042 stokes is = 1.66

Explanation:

Given that,

viscosity of the liquid (μ) = 0.007 poise = $\frac{0.07}{10}$ = 0.007 $\frac{Ns}{m^{2} }$

kinematic viscosity of the liquid (ν) = 0.042 stokes = 0.042$\frac{cm^{2} }{s}$ =0.042×10⁻⁴$\frac{m^{2} }{s}$

The equation for kinematic viscosity of a liquid (μ)= $\frac{viscosity of the liquid}{density of the liquid}$

ie, μ = ν/p = 0.042×10⁻⁴ $\frac{m^{2} }{s}$= $\frac{0.007Ns/m^{2} }{p}$ = p= 1666.67$\frac{kg}{m^{2} }$

Equation for specific gravity of a liquid = $\frac{Density of the liquid}{density of the water}$

we know that, Density of the water = 1000$\frac{kg}{m^{2} }$

specific gravity of the liquid = $\frac{1666.67kg/m^{3} }{1000kg/m^{3} }$= 1.66