Math, asked by saivaibhavgj, 11 months ago

Determine the stability of closed loop control system whose characteristic equation is s5+3s4+5s3+4s2+s+3=0

Answers

Answered by Pitymys
0

Answer:

The system of equation is always stable.

Step-by-step explanation:

CE=S^{5} +3S^{4} +5S^{3} +4S^{2} +S+3

Apply Routh Array method:

S^{n} a_{0} a_{2} a_{4} .........

S^{n-1}a_{1} a_{3}a_{5}.........

S^{n-2}b_{1} b_{2} b_{3}.............

here b_{1} =a_{1} a_{2} -a_{0} a_{ 3}  /a_{1}

       b_{2}  =a_{1} a_{4}-a_{0}a_{5}  /a_{1}

S^{5} 1 5 1..................

S^{4} 3 4 3...............

Here in the first column,the sigh is always positive.Therefore The system is always stable.

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