Question

Determine the strength and molarity of hcl when 0.05m of na2co3

Answer 1

1. The molarity of hydrochloric acid is determined by titrating it against the standard solution of sodium carbonate using methyl orange as indicator.

2. Strength of the acid is determined by multiplying its molarity with its molecular mass which is 36.5.

Chemical Equation :

quantitative-estimation-volumetric-analysis-24

Indicator. Methyl orange.

End Point. Yellow to pink (Acid in burette).

Procedure

1. Take a burette and wash it with water.

2. Rinse the burette with the given solution of hydrochloric acid and fill it with it.

3. Rinse the pipette with the given sodium carbonate solution and pipette out 20 ml of this solution in a washed titration flask.

4. Add 2-3 drops of methyl orange indicator to the titration flask and place it just below the nozzle of the burette over a white glazed tile.

5. Note down the initial reading of the burette and run the acid solution slowly and

dropwise to the titration flask till the colour of the solution changes from yellow to light pink. .

6. Note the final reading and find the volume of hydrochloric acid used.

7. Repeat the procedure to take a set of at least three concordant readings.

Observations

Molarity of Na2CO3 solution = 0.05 M

Volume of Na2CO3 solution taken in each titration = 20.0 ml.

Answer 2

Answer:

The strength of the given solution of hydrochloric acid is 73/xgL⁻¹

Explanation:

The molarity of hydrochloric acid is determined by titrating it against the standard solution of sodium carbonate using methyl orange as indicator.

Strength of the acid is determined by multiplying its molarity with its molecular mass which is 36.5.

Molarity of Na₂CO₃ solution = 0.05 M

Volume of Na₂CO₃ solution taken in each titration = 20.0 ml.

Volume of HCl solution used for neutralising 20.0 mL of 0.05 M Na₂C0₃ solution = ₓ mL

M₁V₁(HCl) / M₂V₂(Na₂CO₃) = Stoichiometric coefficient of HCl/ Stoichiometric coefficient of Na₂CO₃

M₁xₓ/0.05x20.0=2/1

M₁=2x20.0×0.05/ₓ=2/ₓ

Molar mass of HCl= 36.5 g mol⁻¹

Strength of hydrochloric acid = 2/ₓx36.5gL⁻¹

The strength of the given solution of hydrochloric acid is 73/ₓgL⁻¹

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