Chemistry, asked by satish754936, 1 year ago

Determine the strength of KMnO4 solution by titrating against M/10 oxalic acid soluction.

Answers

Answered by AloneButHappy
8
In this titration KMnO4 is the titrant and oxalic acid is the analyte
Potassium permanent is oxidizing agent and oxalic acid is reducing agent
Reaction b/w potassium permanent and oxalic acid is carried out in a acidic medium bcz
Permanent ion in acidic medium is very strong oxidizing agent
Acidity is introduced by adding dil H2so4
MnO4 +8H+5c - - - - - - - - Mn+4H2o
Note:
MnO4 - tive sign
8h +tive sign
5c - tive sign
MN square with +tive sign
Answered by 8625293145shubh
0
Determine the strength of KMnO4 solution by titrating against M/10 oxalic acid soluction.
Similar questions