Question

determine the stress strain and young modulus of a wire 2m long and 0.5mm radius which when stretched by a force 2 kg extend by 2 mm ( g=9.80 m/s square )​

Answer 1

Answer:

0.00052%

Explanation:

Young’s modulus of the material Y=15×10

10

N/m

Diameter d=2mm

Radius r=0.02m

Force F=1kg

Now,

Y=

l

Δl

A

F

l

Δl

=

A×Y

F

l

Δl

×100=[

3.14×(0.002)

2

×15×10

10

9.8

]×100

l

Δl

×100=[

3.14×4×10

−6

×15×10

10

9.8

]×100

l

Δl

×100=[0.052017×10

−4

]×100

l

Δl

×100=0.00052 %

Hence, the percentage increase in length of a wire is 0.00052 %