Determine the sum of all the terms of the following series. 16, 20, 24, _ _ _ _ _, 232, 236
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Sn=a+(n-1)d
=16+(236-1)(20-16)
=16+235×4
=956
=16+(236-1)(20-16)
=16+235×4
=956
rupesh80020:
wrong
Answered by
1
a=16 d=4 an= 236 n=? sn=? an= a+(n-1)d
16+(n-1)*4=236
(n-1) 4=236-16
n-1=220/4
n=55+1
n= 56
Again
sn= n/2(2a+(n-1)d
sn= 56/2(2*16+(56-1)*4
sn= 28(32+55*4)
sn= 28*152
sn = 4256
answer
16+(n-1)*4=236
(n-1) 4=236-16
n-1=220/4
n=55+1
n= 56
Again
sn= n/2(2a+(n-1)d
sn= 56/2(2*16+(56-1)*4
sn= 28(32+55*4)
sn= 28*152
sn = 4256
answer
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