Question

Determine the torque in Newton metres products by a 7.5 HP squirrel cage motor rotating at 1440 rpm

Answer 1

$\huge\mathbb{\green{QUESTION-}}$

Determine the torque in Newton metres products by a 7.5 HP squirrel cage motor rotating at 1440 rpm

$\huge\mathbb{\green{SOLUTION-}}$

$\large\underline{\underline{\sf Given:}}$

• Power (P) = 7.5 hp
• N = 1440 rpm

$\large\underline{\underline{\sf To\:Find:}}$

• Torque ${\sf (\tau)}$.

Now ,

We know that ⎯

✰ 1 Horsepower = 745 Watt

⛬ 7.5 Horsepower = 7.5 × 745

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 5587.5 Watt

N = 1440 rpm

$\implies{\bf \blue{\omega = \dfrac{2πN}{60}}}$

$\implies{\sf \omega = \dfrac{2π×1440}{60}}$

$\implies{\sf \omega = 150.8\:rad/s}$

$\large\implies{\bf \blue{ Torque (\tau)=\dfrac{Power}{\omega} }}$

$\implies{\sf \tau = \dfrac{5587.5}{150.8} }$

$\implies{\bf \red{ \tau = 37\:N-m }}$

$\huge\mathbb{\green{ANSWER-}}$

Torque is ${\bf \red {37\:N-m}}$