Question

determine the total number of outcome a digit natural number is picked at random​

Answer 1

Answer:

99999. So there are a total of (99999 - 10000 + 1) = 90000 5 digit natural numbers

99999. So there are a total of (99999 - 10000 + 1) = 90000 5 digit natural numbersLet us enumerate the count of natural numbers within this range that don’t have a 0 digit in them. In order to do so, let us recognize that we have 5 slots to fill from the digits 1–9. So, the first slot can be filled in 9 ways, the second slot can be filled in 9 ways and so on.

99999. So there are a total of (99999 - 10000 + 1) = 90000 5 digit natural numbersLet us enumerate the count of natural numbers within this range that don’t have a 0 digit in them. In order to do so, let us recognize that we have 5 slots to fill from the digits 1–9. So, the first slot can be filled in 9 ways, the second slot can be filled in 9 ways and so on.So, the count of 5 digit natural numbers that don’t have any 0 digit in any position = 9^5 = 59049

99999. So there are a total of (99999 - 10000 + 1) = 90000 5 digit natural numbersLet us enumerate the count of natural numbers within this range that don’t have a 0 digit in them. In order to do so, let us recognize that we have 5 slots to fill from the digits 1–9. So, the first slot can be filled in 9 ways, the second slot can be filled in 9 ways and so on.So, the count of 5 digit natural numbers that don’t have any 0 digit in any position = 9^5 = 59049Therefore, 90000 - 59049 = 30951 5 digit natural numbers have at least one position occupied by a 0.

99999. So there are a total of (99999 - 10000 + 1) = 90000 5 digit natural numbersLet us enumerate the count of natural numbers within this range that don’t have a 0 digit in them. In order to do so, let us recognize that we have 5 slots to fill from the digits 1–9. So, the first slot can be filled in 9 ways, the second slot can be filled in 9 ways and so on.So, the count of 5 digit natural numbers that don’t have any 0 digit in any position = 9^5 = 59049Therefore, 90000 - 59049 = 30951 5 digit natural numbers have at least one position occupied by a 0.Therefore, the probability of selecting a 5 digit natural number from the set of all 5 digit natural numbers such that at least one position of the selected number is occupied by a 0 digit = 30951/90000 = 3439/10000

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