determine the type of solution the following sustem of linear equations 2x-3y=2 and x-6y=4
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First equation :
2x-3y = 2
2x (a¹x) - 3y (b¹y) - 2 (c¹) = 0 –(1)
Second equation:
x-6y = 4
x(a²x) - 6y(b²y) - 4(c²) = 0 –(2)
On combining equation (1) and (2) :
2x/x = (-3y/-6y) = (-2/-4)
2/1 ≠ 1/2 = 1/2
Now,
a¹/a²≠ b¹/b² = c¹/c²
Then the equations will have no solution.
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