Question

determine the value of a for which the polynomial 2x^4+3x^3+2ax^2+3x+6 is divisible by 1-2x​

Answer 1

Answer:

Step-by-step explanation:

-2x+1 = 0

x = 1/2

2(1/2)⁴+3(1/2)³+2a(1/2)²+3(1/2)+6 = 0

2*1/16+3*1/8+2a*1/4+3*1/2+6 = 0

1/8+3/8+a/2+3/2+6 = 0

1+3+4a+12+48/8 = 0

4a = -64

a = -16

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