Question

Determine the value of a for which the polynomial 4x^4-ax^3+2x^2+4x+3 is divided by (1-2x) .​

Answer 1

Answer:

Step-by-step explanation:

Find the value of a for which the polynomial 2x^4-ax^3+4x^2+2x+1 is divisible by 1-2x

by Yashshrivastava1 02.05.2018

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Answers

THE BRAINLIEST ANSWER!

RishabhBansal

RishabhBansalMaths AryaBhatta

Hey!!!!!

We have

=> 2x⁴ - ax³ + 4x² + 2x + 1 = p(x)

Thus for the divisiblity of 1 - 2x

=> 1 - 2x = 0

=> x = 1/2

Thus P(1/2) = 0

=> 2(1/2)⁴ - a(1/2)³ + 4(1/2)² + 2(1/2) + 1 = 0

=> 2(1/16) - a(1/8) + 4(1/4) + 1 + 1 = 0

=> 1/8 - a/8 + 1 + 1 + 1 = 0

=> 1/8 - a/8 + 3 = 0

=> a/8 = 25/8

=> a = 25

Hope this helps ✌️

Answer 2

Step-by-step explanation:

We can use remainder theorem in this for finding the value of x

1-2x = 0

X = 1/2

Find the remainder

4*1/2^4 - a*1/2^3+2*1/2^2+4*1/2+3

=2⁴ - (a/2)³+1²+2+3

= 16-a³/8 +1 +2 +3

= 22-a³/8

Remainder = 22-a³/8

Now put the value of x in the question

4x^4-ax^3+2x^2+4x+3 / (1-2x) = 22-a³/8

Now you can find the answer

Hope my answer is helpful to you. Please mark my answer as brainlist answer..