Question

Determine the value of a if AB = BC, where A, B, C are the points (-5,1),(0,5) and (a, 1) respectively​

Answer 1

Answer:

a = +5, - 5

Step-by-step explanation:

Given, AB = AC

Squaring both sides,

${AB}^{2} = {AC}^{2}$

Using distance formula,

${(0 - ( - 5))}^{2} + {(5 - 1)}^{2} = {(a - 0)}^{2} + {(1 - 5)}^{2}$

$25 + 16 = {a}^{2} + 16$

${a}^{2} = 25$

a = +5, - 5