determine the value of f(-6) if the function is f(x)=x²+6x+10
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f(-6)= (-6)²+6(-6)+10
f(-6)= 36-36+10
f(-6)= 0+10
f(-6)= 10
f(-6)= 36-36+10
f(-6)= 0+10
f(-6)= 10
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☣ FUNCTIONS ☣

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