Question

Determine the value of h/e. Given K-absorption limit for lead is 0.1 Å and the voltage required to get the K lines is 90 kV.​

Answer 1

Answer:

The value of $\frac{h}{e}$ is found to be 0.228 for the given parameters of the element.

Explanation:

We are given that the K-absorption limit for the given lead is 0.1 Å, while the voltage necessary to get these lines is 90 kV.

We are asked to find the value of $\frac{h}{e}$, which we can find easily if we know the concept well.

We know that the formula (from Moseley's Law) can be written as $Z - 1 = \sqrt{\frac{1}{\lambda R} } \\Z = \sqrt{\frac{1}{(0.1 \times 10^-^1^0) (1.097 \times 10^7)} } + 1 \\\\Z = 74\\\frac{Z}{c} = \frac{nh}{\lambda}\\ \implies \frac{h}{e} = 0.228$

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