Question

Determine the value of k for which k2-4k+8 ,2k+3k +6k,3k2+4k+4 are the consecutive term of ap

Answer 1

when a,b,c are in a.p then 2b=a+c

2(2k+3k+6k)=k2-4k+8+3k2+4k+4

22k=4k2+12

4k2-22k+12=0

there might b a mistake in second term of the given a.p term..

As the approach of the problem is same as the above steps. It can be solved