determine the value of k for which the following pair of linear equation has infinitely many solutions: 12x+ky=k 3y=(k-3)-kx
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The value of k is 6.
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charumathi1:
Can k value be root under 24. substitute k in equation.see my steps carefully my friend
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12x + ky =k
-kx- 3y =-k+3
a1/a2 =b1/b2
12/-k =k/-3
K^2 =24
K =root under 24
-kx- 3y =-k+3
a1/a2 =b1/b2
12/-k =k/-3
K^2 =24
K =root under 24
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