Determine the value of k for which the following system of linear equations has a unique solution: 2x + 5y =7, 3x – 5 = ky
plz answer.............
Answers
Answered by
31
The equations are:
2x + 5y = 7
3x - 5 = ky
3x-ky=5
For the system of equations to have a unique solution, if
a₁/a₂ ≠ b₁/b₂
∴2/3 ≠ 5/-k
∴2/3 ≠ -k/5
5*3/2 ≠ -k
∴15/2 ≠ - k
∴k ≠ -15/2
Hence k can be any real value except -15/2
So k ∈ R - {-15/3}.....
hope it helped you!!!
Regards Brainly Star Community
#shubhendu
2x + 5y = 7
3x - 5 = ky
3x-ky=5
For the system of equations to have a unique solution, if
a₁/a₂ ≠ b₁/b₂
∴2/3 ≠ 5/-k
∴2/3 ≠ -k/5
5*3/2 ≠ -k
∴15/2 ≠ - k
∴k ≠ -15/2
Hence k can be any real value except -15/2
So k ∈ R - {-15/3}.....
hope it helped you!!!
Regards Brainly Star Community
#shubhendu
augustachristy:
thnx man
Answered by
5
k is not equal to -15
2
Step-by-step explanation:
here they are given unique solution
For Unique solution standard formula is a1/a2 is not equal to b1/b2
a1 = 2 , b1 = 5
a2 3 , b2 k
2 = 5
3. k
5 multiplied by 3 is -15 and k multiplied by 2 is 2k
so k is not equal to -15/2
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