Determine the value of k for which the quadratic eqation 4z2 – 2(k + 1) z + (k + 4) = 0 has equal roots
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Answer:
QUADRATIC RESOLUTION
GIVEN EQUATION :
4z² - 2( k + 1 ) z + ( k + 4 ) = 0
FOR EQUAL ROOTS :
D = 0
4 ( k + 1 )² - 4 ( 4 ) ( k + 4 ) = 0
k² + 1 + 2k - 4k - 16 = 0
(k - 1)² = 16
k - 1 = ± 4
k = 5 , -3
Step-by-step explanation:
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5,-3
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