Question

determine the value of k for which the quadratic equation
${x}^{2} - 2(1 + 3k)x + 7(3 + 2k) = 0$
has equal roots...​

Answer 1

Answer:

Heya..here’s ur answer

Step-by-step explanation:

given equation is  

x² + 2x(1 + 3k) +7(3 + 2k) = 0 

or 

x² + 2(1 + 3k)x +7(3 + 2k) = 0 

roots are equal 

we have to find the value of k =? 

now 

we know that an equation have equal roots if and only if D = 0

=> b² -4ac = 0 

here comparing the equation with 

ax² + bx + c = 0 

here 

a= 1, b =  2(1 + 3k) and c=  7(3 + 2k) 

now 

   b² - 4ac = 0

 

=  [ 2(1 + 3k) ]² - 4 ×1×7(3 + 2k)  = 0 

= 4×(1 + 3k)² - 4×7(3 + 2k) = 0

 = 4(1 + 9k² + 6k) - 4(21 +14k) =0

= (1 + 9k² + 6k) - (21 +14k) =0

=> 9k² - 8k -20 = 0 

   now solving the equation we get 

= 9k² - 18k + 10k - 20 = 0

= 9k( k- 2)  + 10(k -2) =0 

=> 9k +10=0 and k -2 = 0

=> k = -10/9 and 2 answer 

✯✯ hope it helps ✯✯

plz mark the brainliest

✌

Answer 2

Step-by-step explanation:

Collect the following data related to Lok Sabha elections - 2019

1. Total seats in Lok sabha (state wise)

2. Major parties (state wise) contesting elections.

3. % of vote share of each party (state wise)

4. Winning candidate..