Question

Determine the value of k for which the quadratic equation 5kx2 + x + 11 = 0 has equal roots.
k-​

Answer 1

Answer:

For equal roots, Discriminant = 0

i.e,

${b}^{2} - 4ac = 0$

$1 - 4 \times 5k \times 11 = 0$

$220k = 1$

$k = \frac{1}{220} \: \: ans.$

Answer 2

Step-by-step explanation:

For equal roots D=0

That is b^2-4ac=0

(1)^2-4*5k*11=0

1-44*5k=0

1-220k=0

1=220k

1/220=k