Question

Determine the value of k for which the quadratic equation kx square - 5 x + k is equal to zero has equal roots

Answer 1

Answer:

Step-by-step explanation:

d= b^2 - 4ac

here  

a=k  

b=-5

and c=k

d= 25-4*k*k

=25-4k^2

4k^2=25

k^2=25/4

k=+/-5/2

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

If the roots of a quadratic eq are equal then

b square - 4ac =0

Here a=k

b = -5

c =k

=> b square -4ac = (-5) square - 4 × k × k=0

25 -4k square = 0

- 4k square = -25

k square = 25/4

k = +-[√25/√4】

= +-5/2

Hence values of j are +5/2 and -5/2

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