Math, asked by Mushfiq, 1 year ago

Determine the value of k for which x=b/a is a solution of kx^2-3abx+2b^2=0.
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Answered by Anonymous
5

Answer:

k=a²

Step-by-step explanation:

kx²-3abx+2b²=0-------------(1)

x=b/a is   solution of equation

means b/x is a root of the equation

hence putting x=b/a in equation (1) we get

k(b/a)²-3ab(b/a)+2b²=0

kb²/a²-3b²+2b²=0

kb²/a²=b²

k=a²b²/b²=a²

so k=a²

Answered by premanshu2334
1

Step-by-step explanation:

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