Question

Determine the value of k for which x=b/a is a solution of kx^2-3abx+2b^2=0

Answer 1

Answer:

k=a²

Step-by-step explanation:

kx²-3abx+2b²=0-------------(1)

x=b/a is   solution of equation

means b/x is a root of the equation

hence putting x=b/a in equation (1) we get

k(b/a)²-3ab(b/a)+2b²=0

kb²/a²-3b²+2b²=0

kb²/a²=b²

k=a²b²/b²=a²

so k=a²