Math, asked by aj2924, 11 months ago

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Determine the value of'k' in the equation (k-3) x2 + X-6= 0 to have real and equal roots​

Answers

Answered by ardabmutiyaar
2

here is your answer

thx

hope it helps you

Attachments:
Answered by rajat2269
6

Answer:

When

b ^{2}  - 4ac = 0

Step-by-step explanation:

1-4×(k-3)×(-6)=0

Or,1+24k-72=0

Or,24k=71

Or,k=71/24

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