Question

determine the value of k such that k+2, 4k-6,3k-2 are in AP​

Answer 1

here is your required answer

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Answer 2

Answer:

Step-by-step explanation:

k + 2 , 4k - 6 and 3k - 2 are in AP if and Only if

(k+ 2) + (3k - 2) = 2(4k - 6)

that is

4k = 8k - 12

that is

4k = 12

that is

k = 3.