Question

determine the value of log 8 to the base 12 + log 8 to the base 12.

Answer 1

$log_{12}(8) + log_{12}(8)$

$log_{ {2}^{4} }( {2}^{3} ) + log_{ {2}^{4} }( {2}^{3} )$

$\frac{3}{4} log_{2}(2) + \frac{3}{4} log_{2}(2)$

$\frac{3}{4} + \frac{3}{4}$

$\frac{6}{4}$

$= \frac{3}{2}$