Question

determine the value of m, if (x+3) is a factor of x^3-3x^2-mx+24​

Answer 1

Answer:

m=10

Step-by-step explanation:

x+3 is a factor

Then -3 is a zero

f(-3)= (-3)³- 3(-3)²-m(-3)+24 =0

f(-3)= -27-27+24+3m=0

f(-3)= -30+3m=0

f(-3)= 3m=30

     = m=10

Thus value of m is 10