Question

Determine the value of 'm',if(x-m)is a factor of polynomial x^3-(m^2-1)x+2. Hence find the value of k,if 3m+6=k

Answer 1

Answer:

The given quadratic expression can be factored as (2x - 3)(x + 1).

So x + 1 = x - m ⇒ m = -1.

Answer 2

The value of m is -2 and the value of k is 6.

Step-by-step explanation:

The given polynomial is

$P(x)=x^3-(m^2-1)x+2$

It is given that (x-m) is a factor of given polynomial. It means P(m)=0.

Substitute x=m in the above equation.

$P(m)=m^3-(m^2-1)m+2$

$P(m)=m^3-m^3+m+2$

$P(m)=m+2$

Equate P(m)=0.

$m+2=0$

$m=-2$

We need to find the value of 3m+6=k.

Substitute m=-2 in 3m+6=k.

$3(-2)+6=k$

$-6+6=k$

$0=k$

Therefore , the value of k is 0.

#Learn more

If x - 1 is a factor of the polynomial 3 x ^2- kx then find the value of k.

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