Question

determine the value of m in the equation that will make the roots equal :

$(m + 1)y { }^{2} + 2(m + 3)y + (2m + 3)$
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Answer 1

Click here to get an answer to your question ✍ without ... given equation has real roots and equal roots : x^2 +2(m-1)x + (m+5)=0 ... EQUATION-x²+x(2m-2 )+( ...

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Without solving the following quadratic equation, find the value of 'm' for which the given equation has real roots and equal roots : x^2 +2(m-1)x + (m+5)=0

Ask for details Follow Report by Tavanya06 28.10.2017

Answers

Rakshitsaini

Rakshitsaini Ace

We know the condition

B^2-4ac>0

[2(m-1)]^2>4*(m+5)

4(m^2-2m+1)>4(m+5)

m^2-3m-4=0

m (-1,4)

3.4

5 votes

THANKS

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Comments (10) Report

07161020

its a too long ques

Rakshitsaini

where

07161020

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07161020

https://brainly.in/question/1665619

Rakshitsaini

I told u late that

I am so bored of doing my maths work lol

07161020

try my ques

Subject??

07161020

maths

Really i am sorry but i am fed up of maths

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THE BRAINLIEST ANSWER!

07161020

07161020 Ace

Hey there,

That's a good question. So let's start from the very beginning!!!

EQUATION-x²+x(2m-2)+(m+5)

If the roots are to be real and equal then the value of discriminant(D) is to be 0.

D=0

(2m-2)²-4(m+5)=0

4m²-12m-16=0

Taking 4 as common, we get-

m²-3m-4=0

m²+4m-m-4=0

m(m+4)-1(m+4)=0

(m-1)(m+4)=0

Therefore m=1 or m=-4

PLEASE MARK AS BRAINLIEST IF HELPFUL!!!

Answer 2

m = -2 and 3

You can solve by using quadratic formula....

plz mark as brainliest, if helpful....