Question

determine the value of m which the equatiin x²+m(4x+m-1)+2=0 has real root​

Answer 1

Answer:

an^+bn+c=0

D>0 ✓

x^+m(4x+m-1)+2=0

x^+4mn+m^-m+2=0

D>0

16m^-4(m^-m+2)>0

cut 4 to 16 in 4 times.

Then,

4m^-m^+m-2>0

3m^+m-2>0

Now take factors of m-2 which is : 3m and 2m

Now,

3m^+3m-2m-2>0

(3m-1)(m+1)>0

If the interval of x will be in between

m€(-infinity , -1 )(1/3, infinity).

Then the value of this equation will

always have real roots.

Answer 2

I hope this will help you

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