Math, asked by danish8598, 1 year ago

Determine the value of p for which the following
quadratic equation has real roots: 2x2 + px +8= 0

Answers

Answered by skkokila18
9

Answer:

Step-by-step explanation:

for real root, b^2 - 4ac ≥0

          so a = 2 , b= p , c = 8

                      p^2 - 4 x 2 x 8 =0

                       p^2 - 64 = 0

                       p^2 = 64

                         p = ±√64 = ± 8

so p= ± 8

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