Math, asked by shadmaashadma2377, 1 year ago

Determine the value of p given quadratic equation has real roots 4^x2+8x-p=0

Sakshi15403: does it have real and equal roots?

Sakshi15403: has*

Answers

Answered by Sakshi15403

HOPE IT WILL HELP YOU... :-)

Attachments:

ALTAF11: it is given that roots are real but it isn't given that roots are equal

Sakshi15403: yeah,...if it's not equal then it'll be p>-4

Sakshi15403: greater than 4...

ALTAF11: D > 0 n ..edit it

ALTAF11: D will greater than 0

Sakshi15403: But there are two conditions na...! maybe equal or unequal...the inquirer should have clarified it...

Answered by mysticd

Hi ,

Compare 4x² + 8x - p = 0 with

ax² + bx + c = 0 ,

a = 4 ,b = 8 , c = - p

Discreaminant = D = b² - 4ac = 0

1 ) if roots are real

D > 0

b² - 4ac > 0

8² - 4 × 4 × ( -p )>0

64 + 16 p > 0

16 p > - 64

p >- 64/16

p > - 4

2 )If it has equal real roots .

8² - 4 × 4 × ( - p ) = 0

64 + 16p = 0

16 ( 4 + p ) = 0

4 + p = 0

p = - 4

Therefore ,

If p = -4 , the given equation has real

and equal roots.

I hope this helps you.

: )

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