Question

determine the value of the following log1to the base7​

Answer 1

To find:

\textsf{The value of}The value of

\mathsf{\log_{7}1}log

7

1

\underline{\textsf{Solution:}}

Solution:

\bf\mathsf{Concept:}Concept:

\boxed{\mathsf{a^x=N\;\iff\;\log_aN=x}}

a

x

=N⟺log

a

N=x

\mathsf{Consider,}Consider,

\mathsf{Let\;\;\log_{7}1=x}Letlog

7

1=x

\implies\mathsf{7^x=1}⟹7

x

=1

\implies\mathsf{7^x=7^0}⟹7

x

=7

0

\mathsf{Equating\;powers\;on\;bothsides,\;we\;get}Equatingpowersonbothsides,weget

\mathsf{x=0}x=0

\implies\boxed{\mathsf{\log_{7}1=0}}⟹

log

7

1=0

\underline{\textsf{Find more:}}

Answer 2

$ANSWER</p><p></p><p>log71=log7log1=0</p><p></p><p></p><p>$

hope it's helpful....!!!