Question

Determine the value of x in
$( \frac{2}{3} ) {}^{3} \times ( \frac{2}{3} ) {}^{ - 6} = ( \frac{2}{3} ) {}^{2x - 1}$

​

Answer 1

Step-by-step explanation:

$( \frac{2}{3} ) ^{3} \times ( \frac{2}{3} ) ^{ - 6} = ( \frac{2}{3}) ^{2x - 1}$

since the base of all exponent is same

==> 3+ (-6) = 2x -1

==> -3 +1 = 2x

==> -2 = 2x

==>

$- 1 = x$

Answer 2

Answer:

3/9 is the answerrrrrrrr brooooo