determine the value of x.....please solve it
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Q.6 (a)
three angles of a triangle are 4x,5x+6,9x-6.
thus, by angle sum property,
4x+5x+6+9x-6=180
18x=180
x=10. thus, angles are 40,56,84.
(b).three angles of a triangle are 2x, 3x,5x.
thus, by a.s.p,
2x+3x+5x=180
10x=180
x=18. thus, angels are 36,54,90.
(c)three angles of a triangle are in ratio 3:4:5. let the required ratio be x
so, 3x+4x+5x=180
12x=180
x=15. thus, angles are 45,60,75.
hope it helps!!!!
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