Question

. Determine the value of x such that
2 cosec+30° + x sin?60° - tan° 30° = 10.​

Answer 1

Answer:

x=2(2$\sqrt{3\\}$-1)

Step-by-step explanation:

2cosec30 + xsin60 -tan30 =10

2(2)+x($\sqrt{3}$/2)-$\sqrt{3}$=10

x($\sqrt{3}$/2)=6-$\sqrt{3\\}$

x=6-$\sqrt{3\\}$/($\sqrt{3}$/2)

x=2(2$\sqrt{3\\}$-1)

Answer 2

Answer:

x=2(2-1)

Step-by-step explanation:

2cosec30 + xsin60 -tan30 =10

2(2)+x(/2)-=10

x(/2)=6-

x=6-/(/2)

x=2(2-1)