Question

determine the value of x+y+z, if x^2+y^2+z^2=50 and xy+yz+zx=7.​

Answer 1

Answer:

Step-by-step explanation:

We know that-

(x+y+z)²= x² + y² + z² + +2xy + 2yz + 2zx

(x+y+z)² = 50 + 2(7)

(x+y+z)² = 50 + 14 = 64

x + y + z = $\sqrt{64}$ = 8

I hope this helps you . . . please comment if further doubt.